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MySql数据查重、去重的实现
阅读量:4147 次
发布时间:2019-05-25

本文共 1858 字,大约阅读时间需要 6 分钟。

假设有一个表user,字段分别有id–nick_name–password–email–phone,分情况如下(注意删除多余记录时要创建临时表,不然会报错):

一、单字段(nick_name)

1、查出所有有重复记录的所有记录

select * from user where nick_name in     (select nick_name from user group by nick_name having count(nick_name)>1);

2、查出有重复记录的各个记录组中id最大的记录

select * from user where id in (select max(id) from user group by nick_name having count(nick_name)>1);

3、查出多余的记录,不查出id最小的记录

select * from user where nick_name in     (select nick_name from user group by nick_name having count(nick_name)>1)and id not in      (select min(id) from user group by nick_name having count(nick_name)>1);

4、删除多余的重复记录,只保留id最小的记录

delete from user where nick_name in     (select nick_name from          (select nick_name from user group by nick_name having count(nick_name)>1) as tmp1)and id not in       (select id from           (select min(id) from user group by nick_name having count(nick_name)>1) as tmp2);

二、多字段(nick_name,password)

1、查出所有有重复记录的记录

select * from user where (nick_name,password) in     (select nick_name,password from user group by nick_name,password where having count(nick_name)>1);

2、查出有重复记录的各个记录组中id最大的记录

select * from user where id in     (select max(id) from user group by nick_name,password where having count(nick_name)>1);

3、查出各个重复记录组中多余的记录数据,不查出id最小的一条

select * from user where (nick_name,password) in     (select nick_name,password from user group by nick_name,password having count(nick_name)>1)and id not in     (select min(id) from user group by nick_name,password having count(nick_name)>1);

4、删除多余的重复记录,只保留id最小的记录

delete from user where (nick_name,password) in     (select nick_name,password from          (select nick_name,password from user group by nick_name,password having count(nick_name)>1) as tmp1)and id not in     (select id from          (select min(id) id from user group by nick_name,password having count(nick_name)>1) as tmp2);

 

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